Matematică, întrebare adresată de lukasttv443, 8 ani în urmă

exercițiul 4, tot cu probă
Dau coroanaaaa promit​

Anexe:

Răspunsuri la întrebare

Răspuns de ungureanualesia30
1

Răspuns:

a)22:2= 11 rest 0

11:2 = 5 rest 1

5÷2= 2 rest 1

2÷2= 1 rest 0

1÷2= 0 rest 1

22(in baza 10)= 10110(in baza 2)

( in Se iau resturile in seen invers ( de jos in sus)

b)39÷2= 19 rest 1

19÷2= 9 rest 1

9÷2= 4 rest 1

4÷2= 2 rest 0

2÷2= 1 rest 0

1÷2= 0 rest 1

39(in baza 10)=100111(in baza 2)

( in Se iau resturile in seen invers ( de jos in sus)

c)33÷2= 16 rest 1

16÷2= 8 rest 0

8÷2= 4 rest 0

4÷2= 2 rest 0

2÷2= 1 rest 0

1÷2= 0 rest 1

33(in baza 10)=100001(in baza 2)

( in Se iau resturile in seen invers ( de jos in sus)

d)41÷2= 20 rest 1

20÷2= 10 rest 0

10÷2= 5 rest 0

5÷2= 2 rest 1

2÷2= 1 rest 0

1÷2= 0 rest 1

41(in baza 10)=100101(in baza 2)

( in Se iau resturile in seen invers ( de jos in sus)

e)51÷2= 25 rest 1

25÷2= 12 rest 1

12÷2= 6 rest 0

6÷2= 3 rest 0

3÷2= 1 rest 1

1÷2= 0 rest 1

51(in baza 10)=110011(in baza 2)

( in Se iau resturile in seen invers ( de jos in sus)

f)47÷2= 23 rest 1

23÷2= 11 rest 1

11:2 = 5 rest 1

5÷2= 2 rest 1

2÷2= 1 rest 0

1÷2= 0 rest 1

47(in baza 10)=111101(in baza 2)

( in Se iau resturile in seen invers ( de jos in sus)

g)25÷2= 12 rest 1

12÷2= 6 rest 0

6÷2= 3 rest 0

3÷2= 1 rest 1

1÷2= 0 rest 1

25(in baza 10)=10011(in baza 2)

( in Se iau resturile in seen invers ( de jos in sus)

h)75÷2= 37 rest 1

37÷2= 18 rest 1

18÷2= 9 rest 0

9÷2= 4 rest 1

4÷2= 2 rest 0

2÷2= 1 rest 0

1÷2= 0 rest 1

75(in baza 10)=1101001(in baza 2)

( in Se iau resturile in seen invers ( de jos in sus)

Succes!!


lukasttv443: Mulțumesc!!
lukasttv443: da dar nu pot sa îți dau coroana. :'(
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