Question

exercitiul 4 !!!! urgent!!!! dau coroana!!!

Answer 1

atasez rezolvarea completa a exercitiului :)

Answer 2

[tex]\it \dfrac{423}{25} = 16\dfrac{23}{25} \Rightarrow inegalitatea\ devine: \\ \\ \\ 16\dfrac{\overline{8a}}{90} \ \textless \ 16\dfrac{23}{25} \Rightarrow \dfrac{\overline{8a}}{90} \ \textless \ \dfrac{23}{25} \Rightarrow \dfrac{\overline{8a}}{90} \ \textless \ 0,92 \Rightarrow \overline{8a} \ \textless \ 0, 92\cdot 90 \Rightarrow \\ \\ \\ \overline{8a} \ \textless \ 82,8 \Rightarrow a\in\{0,\ 1,\ 2\}[/tex]