Matematică, întrebare adresată de SeliaLas, 9 ani în urmă

EXERCITIUL 4 Va rog!E super easy dar eu l-am cam uitat

Anexe:

Răspunsuri la întrebare

Răspuns de Coco0987
1
(2/3)^4x5  x (2/3) ^10 :( (2/3)^2)^14 =
(2/3)^20 x (2/3)^10 : (2/3)^28=
(2/3)^20+10 : (2/3)^28=
(2/3)^30 : (2/3)^28=
(2/3)^30-28=
(2/3)^2=2^2/3^2=4/9


Răspuns de Utilizator anonim
0
(2/3)^4x5 x (2/3) ^10 :( (2/3)^2)^14 =
(2/3)^20 x (2/3)^10 : (2/3)^28=
(2/3)^20+10 : (2/3)^28=
(2/3)^30 : (2/3)^28=
(2/3)^30-28=
(2/3)^2=2^2/3^2=4/9
Sper ca te-am ajutat.
Alte întrebări interesante