Question

exercițiul 4 vă rog frumos

Answer 1

Răspuns

Explicație pas cu pas:

a.  1 si 3\4+2 si 7\9=7\4+25\9=(63+100)\36=163\36                     b. b.    3 si 5\6+1 si 2\5=23\6+7\5=(115+42)\30=157\30

c.   4 si 1\15+3 si 2\30=61\15+92\30=(122+92)\30=214\30=107\15

d.  2 si 1\21+3 si 1\7=42\21+22\7=(42+66)\21=108\21=36\7

e.  4 si 1\16+1 si 3\8=65\16+11\8=(65+22)\16=87\16

f.  2 si 3\5+1 si 2\15=13\5+17\15=(39+17)\15=56\15

g.  3 si 1\24 +2 si 3\18=73\24+39\18=(219+156)\72=375\72=125\24

h.   4 si 1\25+1 si 2\20=101\25+22\20=(404+110)\100=514\100=257\50

Answer 2

Răspuns

Explicație pas cu pas:

4).→ introduc intregii in fractie

a) 1 intreg si 3 / 4 = ( 1 x 4 + 3 ) / 4 = 7 / 4

2 intregi si 7 / 9 = ( 2 x 9 + 7 ) / 9 = 25 / 9

7 / 4 + 25 / 9 =  →  le aduc la acelasi numitor comun 36

= ( 7 × 9 ) / 36 + ( 25 × 4 ) / 36 =

= ( 63 + 100 ) / 36 =

= 163 / 36 =

= 4 intregi si 19 / 36

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b)  3 intregi si 5 / 6 = ( 3 x 6 + 5 ) / 6 = 23 / 6

1 intreg si 2 / 5 = ( 1 x 5 + 2 ) / 5 = 7 / 5

= 23 / 6 + 7 / 5 =  → c.m.m.m.c al numitorilor ( 6 si 5 ) = 30

= ( 23 × 5 ) / 30 + ( 7 × 6 ) / 30 =

= ( 115 + 42 ) / 30 =

= 157 / 30 =

= 5 intregi si 7 / 30

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c) 4 intregi si 1 / 15 = 61 / 15  si  3 intregi si 2 / 30 = 92 / 30

61 / 15 + 92 / 30 =

= ( 61 × 2 ) / 30 + 92 / 30 =

= ( 122 + 92 ) / 30 =

= 214 / 30 =

= 107 / 15 =

= 7 intregi si 2 / 15

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d) 2 intregi si 1 / 21 = 43 / 21   si  3 intregi si 1 / 7 = 22 / 7

= 43 / 21 + 22 / 7 = → le aduc la acelasi numitor comun 21

= 43 / 21 + ( 22 × 3 ) / 21 =

= ( 43 + 66 ) / 21 =

= 109 / 21 =

= 5 intregi si 4 / 21

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e) 4 intregi si 1 / 16 = 65 / 16  si  1 intreg si 3 / 8 = 11 / 8

= 65 / 16 + 11 / 8 =

= ( 65 + 22 ) / 16 =

= 87 / 16 =

= 5 intregi si 7 / 16

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f) 2 intregi si 3 / 5 =( 2 x 5 + 3 ) / 5 = 13 / 5

1 intreg si 2 / 15 = ( 1 x 15 + 2 ) / 15 = 17 / 15

= 13 / 5 + 17 / 15 =

= ( 13 × 3 ) / 15 + 17 / 15 =

= ( 39 + 17 ) / 15 =

= 56 / 15 =

= 3 intregi si 11 / 15

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g)   3 intregi si 1 / 24 = ( 3 x 24 + 1 ) / 24 = 73 / 24

2 intregi ai 3 / 18 = 2 intregi 1 / 6 = 13 / 6

= 73 / 24 + 13 / 6 =

= 73 / 24 + ( 13 × 4 ) / 24 =

= ( 73 + 52 ) / 24 =

= 125 / 24 =

= 5 intregi si 5 / 24

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h)  4 intregi si 1 / 25 = ( 4 x 25 + 1 ) / 25 = 101 / 25

1 intreg si 2 / 20 = 1 intreg si 1 / 10 = 11 / 10

= 101 / 25 + 11 / 10 =  → c.m.m.m.c al numitorilor ( 25 si 10 ) = 50

= ( 101 × 2 ) / 50 + ( 11 × 5 ) / 50 =

= ( 202 + 55 ) / 50 =

= 257 / 50 =

= 5 intregi si 7 / 50