Question

Exercitiul 4 va rog si cu explicatie

Answer 1

5[2(3I2x-5I-11)-13]-27=8
2x-5>0
I2x-5I=2x-5
5{2[3(2x-5)-11]-13}-27=8
5[2(6x-15-11)-13]=35
2(6x-26)-13=7
2(6x-26)=20
6x-26=10
6x=36
x=6

2x-5<0
I2x-5I=-(2x-5)=5-2x
5{2[3(5-2x)-11]-13}-27=8
5[2(15-6x-11)-13]=35
2(4-6x)-13=7
2(4-6x)=20
4-6x=10
6x=-6
x=-1