Matematică, întrebare adresată de ionik96, 8 ani în urmă

Exercitiul 4 va roooooogg

Anexe:

Răspunsuri la întrebare

Răspuns de iakabcristina2
0

a)x(x-7)

b)x(x+3)

c)5x^4(x^2 + 5)

d)(x+5)(x^2 + x^2 + 5x) = x(x+5)(2x+5)

e)a^2(b-1) - (b-1) = (b-1)(a-1)(a+1)

f)5x(5y+1) - (5y+1) = (5y+1)(5x-1)

g)7x(7y-1) + (7y-1) = (7y-1)(7x+1)

h)(7x-11)(7x+11)

i)(x-3-3x)(x-3+3x)=(-4x-3)(4x-3)=-(4x+3)(4x-3)

j)(x+3-5x)(x+3+5x)=(-4x+3)(6x+3)=-3(4x-3)(2x+1)

k)(x+6)^2 - y^2 = (x+6-y)(x+6+y)

l)x^2 + 2x + 9x + 18 = x(x+2) + 9(x+2) = (x+2)(x+9)

m)x^2 - 3x - 4x + 12 = x(x-3) - 4(x-3) = (x-3)(x-4)

n)x^2 + 6x - x - 6 = x(x+6) - (x+6) = (x+6)(x-1)

o)x(x^2 + x - 2010) - 2010 =

???

Răspuns de gabybalint1
0

:a)x(x-7)

b)x(x+3)

c)5x^4(x^2 + 5)

d)(x+5)(x^2 + x^2 + 5x) = x(x+5)(2x+5)

e)a^2(b-1) - (b-1) = (b-1)(a-1)(a+1)

f)5x(5y+1) - (5y+1) = (5y+1)(5x-1)

g)7x(7y-1) + (7y-1) = (7y-1)(7x+1)

h)(7x-11)(7x+11)

i)(x-3-3x)(x-3+3x)=(-4x-3)(4x-3)=-(4x+3)(4x-3)

j)(x+3-5x)(x+3+5x)=(-4x+3)(6x+3)=-3(4x-3)(2x+1)

k)(x+6)^2 - y^2 = (x+6-y)(x+6+y)

l)x^2 + 2x + 9x + 18 = x(x+2) + 9(x+2) = (x+2)(x+9)

m)x^2 - 3x - 4x + 12 = x(x-3) - 4(x-3) = (x-3)(x-4)

n)x^2 + 6x - x - 6 = x(x+6) - (x+6) = (x+6)(x-1)

o)x(x^2 + x - 2010) - 2010

Coroana?

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