Question

Exercitiul 5, repede.
Multumesc.

Answer 1

5
x²-7x+10=(x-2)(x-5)
Rezolvam prima paranteza unde aducem la acelasi numitor (x-2)(x-5)

E(x)=2(x-2)/[(x-2)(x-5)]+(x-5)/[(x-2)(x-5)] - (x-9)/[(x-2)(x-5)] . [(x-2)(x-5)]/x
Simplificam numitorul primei paranteze cu numaratorul (x-2)(x-5)

E(x)=(2x-4)/x + (x-5)/x + (-x +9)/x
E(x)=(2x-4+x-5-x+9)/x
E(x)=2x/x
E(x)=2