Question

Exercițiul 5 va rog ​

Answer 1

5

a) $\frac{0,2}{\frac{37}{10}}=\frac{x}{30*(\frac{2*3+2}{3}+\frac{35}{10})}$ <=> $\frac{2}{10}*\frac{10}{37}=\frac{x}{30*(\frac{8}{3}+\frac{7}{2})}$ <=> $\frac{2}{37}=\frac{x}{30*\frac{16+21}{6}}$ <=> $\frac{2}{37}=\frac{x}{5*37}$ <=>

x=10

b) $\frac{x}{1,2}=\frac{(2,5-1\frac{2}{3})^{2}}{\frac{5}{24}}$ <=> $\frac{x}{\frac{12}{20}}=\frac{(\frac{25}{10}-\frac{5}{3})^{2}}{\frac{5}{24}}$ <=> $\frac{x}{\frac{12}{10}}=\frac{(\frac{15-10}{6})^{2}}{\frac{5}{24}}$ <=> $\frac{x}{\frac{12}{10}}=\frac{5^{2}}{36}*\frac{24}{5}$ <=> $\frac{x}{\frac{12}{10}}=\frac{5*2}{3}$ <=> $x=\frac{10}{3}*\frac{12}{10} <=> x=4$

c) $\frac{8\frac{8}{15}*{[0,2+x*(1\frac{1}{3}-1,2)]*1,(6)}}{2,1(3)}=\frac{2^{32}}{4^{15}}$ <=> $\frac{\frac{8*15+8}{15}*{[\frac{2}{10}+x*(\frac{3+1}{3}-\frac{12}{10})]*\frac{15}{9}}}{\frac{32}{15}}=\frac{2^{32}}{4^{15}}$ <=> $\frac{\frac{128}{15}*{[\frac{1}{5}+x*(\frac{4}{3}-\frac{6}{5})]*\frac{5}{3}}}{\frac{32}{15}}=\frac{2^{32}}{2^{30}}$ <=> $\frac{\frac{128}{15}*[(\frac{1}{5}+x*\frac{20-18}{15})*\frac{5}{3}]}{\frac{32}{15}}=4$ <=> $\frac{\frac{128}{15}*(\frac{1}{3}+x*\frac{2}{9})}{\frac{32}{15}}=4$ <=> $\frac{128}{15}*\frac{15}{32}*(\frac{1}{3}+x*\frac{2}{9})=4$ <=> 2x=6 <=> x=3