Question

Exercitiul 6 b) DAU COROANA

Answer 1

{9+4•[5-(a+3):4]}•[27-(7+12:b)•2]=13
13 e număr prim, deci
I.{9+4•[5-(a+3):4]}=1 si [27-(7+12:b)•2]=13
II. {9+4•[5-(a+3):4]}=13 si [27-(7+12:b)•2]=1
I. {9+4•[5-(a+3):4]}=1 —>4•[5-(a+3):4]=9-1=8 —> 5-(a+3):4=8:4=2 —>(a+3):4=5-2=3–> (a+3)= 3•4=12 —> a=12-3=9
[27-(7+12:b)•2]=13–> (7+12:b)•2=27-13=14 —> 7+12:b=14:2=7–>12:b=7-7=0–>b=0

II. {9+4•[5-(a+3):4]}=13–> 4•[5-(a+3):4]=13-9=-4 —> 5-(a+3):4=(-4):4=-1 —> (a+3):4=5-(-1)=6–> a+3=6•4=24 —> a=21
[27-(7+12:b)•2]=1 —>(7+12:b)•2=27-1=26 —> 7+12:b=26:2=13 —> 12:b=13-7=6 —> b=12:6 —> b=2