Question

Exercitiul 6 plzzz
repedee

Answer 1

I.p:{-fie ΔABC si M∈BC ⇔ AM⊥BC}
C.{ Aabm+Aacm=Aabc}
Dem.{-notam AM=a, BM=b si CM=c ⇔ Aabm=ab/2 ; Aacm=ac/2 inlocuim in relatie si obtinem: ab+ac/2=a(b+c)/2=AM·BC/2=Aabc}