Question

exercițiul 6 va rog muuult

Answer 1

|x^2-7x+5|=1 <=> x^2-7x+5=1 sau x^2-7x+5=-1 <=> x^2-7x+4=0 sau x^2-7x+6=0.

x^2-7x+4=0
delta=(-7)^2-4*1*4=49-16=33.
x_1,2=(7+-rad(33))/2

x^2-7x+6=0
delta=(-7)^2-4*1*6=49-24=25.
x_3,4=(7+-rad(25)/2=(7+-5)/2. => x_3=6 si x_4=1.

In concluzie, x_1=(7+rad(33))/2; x_2=(7-rad(33))/2; x_3=6; x_4=1.