Question

Exercițiul 6 ! Va rooog

Answer 1

$a)~\frac{2x}{3y}=\frac{1}{2}$
$Calculam~pe~diagonala~$
$\frac{x}{y}=\frac{3}{4}$
$x=3k~ ;~ y=4k$

$b)\frac{2x-y}{x+y}=\frac{2*3k-4k}{3k+4k}=$
$\frac{6k-4k}{7k}=\frac{2k}{7k}$
$Simplificam~prin~k=\frac{2}{7}$