Question

Exercitiul 8,nu am inteles la scoala

Answer 1

ADC =dreptunghic  ; AC = ipotenuza
=> AD^2 =AC^2-CD^2
AD^2 =27^2-16.2^2 
AD^2 =729-262.44 =466.56
AD = RADICAL DIN 466.56 =21.6 cm
 AC^2 =BC *CD
27^2 =BC*16.2
729 =BC*16.2
BC =729:16.2 =45 CM
 
BD =BC-16.2
BD =45-16.2 =28.8 cm

AB^2 =BD^2+AD^2
AB^2 =28.8^2+21.6^2
AB^2 =829.44+466.56 =1296
AB =rad din 1296 =36 cm
 
b )
BC =BD+CD
BC =27+48 =75 cm
AB^2 =BC*BD
AB^2 =75*27 =2025
AB = bad din 2025 =45 cm

AC^2=BC*CD
AC^2 =75*48 =3600
AC = rad din 36  =60 cm