Question

exercitiul 9 pagina 44 dau coroana​

Answer 1

x + y/2 + z/3 + t/4 = 1/8

Avem si 1/x = 2/y = 3/z = 4/t = k

x = 1/k

2/y=k -> y/2=1/k

3/z=k -> z/3=1/k

4/t=k -> t/4=1/k

Inlocuind in prima ecuatie, gasim: 1/k + 1/k + 1/k + 1/k = 1/8

4/k = 1/8

k = 32

Deci: x=1/32

y = 2/32 = 1/16

z=3/32

t=4/32 = 1/8