Question

Exercițiul 9 va rog!!

Answer 1

A(-2;4); B(2;2); C(-1;-1)

M mijlocul lui BC

M(xM; yM);  

xM=(xB+xC)/2=(2-1)/2=1/2

yM=(yB+yC)/2=(2-1)/1=1/2

=> M(1/2; 1/2)

AM=√[(xM-xA)²+(yM-yA)²]

AM=√[(1/2+2)²+(1/2-4)²]= √(25/4+49/4)=√(74/4)=√74 / 2  u

D.  √74 / 2   u