Question

Exercitiul cu scoateti de sub radical, rapiddd

Answer 1

$\boxed{\bf {2}^{3} \cdot {5}^{4}\cdot {3}^{3}\cdot {7}^{5} \cdot {11}^{2} \cdot\sqrt{ 21}}$

Explicație pas cu pas:

$\bf \sqrt{ {2}^{6} \cdot {3}^{7} \cdot {5}^{8} \cdot {7}^{11}} \cdot {11}^{2} =$

$\bf \sqrt{ ({2}^{3})^{2} \cdot {3}^{6} \cdot3 \cdot ({5}^{4})^{2} \cdot {7}^{10} \cdot7} \cdot {11}^{2} =$

$\bf {2}^{3} \cdot {5}^{4} \cdot\sqrt{({3}^{3})^{2}\cdot 3 \cdot ({7}^{5})^{2} \cdot7} \cdot {11}^{2} =$

$\bf {2}^{3} \cdot {5}^{4}\cdot {3}^{3}\cdot {7}^{5} \cdot\sqrt{ 3\cdot7} \cdot {11}^{2} =$

$\boxed{\bf {2}^{3} \cdot {5}^{4}\cdot {3}^{3}\cdot {7}^{5} \cdot {11}^{2} \cdot\sqrt{ 21}}$

sau faci ridicarile la putere si înmulțirile

$\bf 8 \cdot 625\cdot 27\cdot 16807 \cdot 121 \cdot\sqrt{ 21}=$

$\bf 16335000\cdot 16807 \cdot\sqrt{ 21}=$