Question

Exercițiul E10. Mulțumesc anticipat! ​

Answer 1

Răspuns:

Explicație pas cu pas:

f(3)=0

f(0)=$\frac{1}{2}$

$f(3)=\frac{9m^{2} -3(m+1)+1}{9+n} =0\\\\\\f(0)=\frac{1}{n} =\frac{1}{2}$

n=2

$f(3)=\frac{9m^{2} -3(m+1)+1}{9+2} =0$

9m²-3m-3+1=0

9m²-3m-2=0

Δ=9+72=81

$m_{1}=\frac{3+9}{18} =\frac{2}{3} \\\\\\m_{2}=\frac{3-9}{18}=-\frac{1}{3}$