Question

Exercitiul patru....

Answer 1

[tex]a=(^{12)}\frac{4}{5\sqrt{3}}-^{15)}\frac{3}{4\sqrt{3}}-^{10)}\frac{3}{6\sqrt{3}})\cdot (-\frac{4\sqrt{3}}{3\sqrt{2}})\cdot \frac{10\sqrt{2}}{3}=\\ \frac{48-45-30}{60\sqrt{3}}\cdot(-\frac{4\sqrt{3}}{3\sqrt{2}})\frac{10\sqrt{2}}{3}=\\ -\frac{27}{60\sqrt{3}}\cdot(-\frac{4\sqrt{3}}{3\sqrt{2}})\cdot\frac{10\sqrt{2}}{3}=\\ +\frac{27}{60}\cdot \frac{4}{3}\cdot \frac{10}{3}=2 [/tex]