Question

Existenta Cl- din apa potabila poate fi pusa in evidenta cu AgNo3 cand precipita clorura de Ag conform ecuatiei:
Ag+(aq)+Cl- (aq)→AgCl(s)
Calculati numarul de ioni Ag+ care conduce la obtinerea a 28,7 grame precipitat alb.

Answer 1

MAgCl=108+35,5=143,5g/mol
1mol..........................143,5g
Ag+(aq) + Cl-(aq) -> AgCl(s)
x=?............................28,7g
x=28,7/143,5=0,2moli Ag+
1mol Ag+..............6,0225*10²³ ioni
0,2moli.....................................y ioni
y=0,2*6,0225*10²³=1,2045*10²³ ioni Ag+