Question

explicati-mi va rog cum pot face calculul.multumes​c

Answer 1

Modul de a inseamna a daca a>=0, sau -a daca a<0.

Modul(2-rad(6))=rad(6)-2, deoarece rad(6)>2;

Modul(3-rad(6))=3-rad(6), deoarece 3>rad(6);

Modul(-2 1/5)=2 1/5=11/5

Obtinem:

Rad(6)-2+3-rad(6)+11/5=1+11/5=16/5

Answer 2

Răspuns:

Explicație pas cu pas:

Se aplica definitia modulului, |a|=a, daca a≥0 si |a|=-a, daca a<0.

$|2-\sqrt{6}|+|3-\sqrt{6} |+|-2\frac{1}{5}|=???\\2=\sqrt{4}<\sqrt{6},~deci~2-\sqrt{6}<0,~deci~ |2-\sqrt{6}|=-(2-\sqrt{6})=-2+\sqrt{6} .\\3=\sqrt{9}>\sqrt{6},~deci~ 3-\sqrt{6}>0,~deci~|3-\sqrt{6}|=3-\sqrt{6}.\\|-2\frac{1}{5}|=-(-2\frac{1}{5})=+2\frac{1}{5}.Atunci,\\|2-\sqrt{6}|+|3-\sqrt{6} |+|-2\frac{1}{5}|=-2+\sqrt{6} +3-\sqrt{6}+2\frac{1}{5}=1+2\frac{1}{5}=3\frac{1}{5}$