Question

explicati modulul:
|1-√7| |-√3-√2| |8-√49| |(3-√2)²| {x∈R ||x|≤7}

Answer 1

$|1-\sqrt7|=\sqrt7-1 \\ |-\sqrt3-\sqrt2|=\sqrt3+\sqrt2 \\ |8-\sqrt{49}|=1 \\ |(3-\sqrt2)^2|=11-6\sqrt2 \\ [-7,7]$



$[-7;7]$