Question

explicitați modulul. |2√17-9|​

Answer 1

$2 \sqrt{17} = \sqrt{ {2}^{2} \times 17} = \sqrt{68}$

$9 = \sqrt{81}$

$\sqrt{81} > \sqrt{68} = >$

$| 2\sqrt{17} - 9 | = - 2 \sqrt{17} + 9$