Question

Expresie de x . Please help me !

Answer 1

[tex]E(x)= \frac{x+1}{x^2+1}: \frac{(x-1)^2-x(x-2)}{x^2+1} \\ \\ E(x)= \frac{x+1}{x^2+1}* \frac{x^2+1}{x^2-2x+1-x^2+2x} \\ \\ E(x)= \frac{x+1}{1} \\ \\ \boxed{E(x)=x+1} [/tex]

Answer 2

E(x)=1 se mai scrie:

$\frac{x+1}{ x^{2} +1} : \frac{ (x-1)^{2} -x(x-2)}{ x^{2} +1}$ = 1, adica:


$\frac{x+1}{ x^{2} +1}$ = $\frac{ (x-1)^{2} -x(x-2)}{ x^{2} +1}$ si cum

$x^{2} +1$ > 0 pentru orice x∈R rezulta ca:

x+1 = $(x-1)^{2} -x(x-2)$, adica:

x+1 = $x^{2} -2x+1- x^{2} +2x$, de unde:

x+1 = 1, deci:

x = 0