Question

Exprima in kelvini urmatoarele temperaturi

t= 27 C

t= -273,15 C

t= -123 C


2. Transforma in scara Celsius urmatoarele temperaturi

T= 73K

T=290K

T=400K

Answer 1

• TK= tC + 273,15

1.

t= 27 C

TK= tC + 273,15

T= 27+273,15 = 300,15 K

t= -273,15 C

T= -273,15 + 273,15 = 0 K

t= -123 C

T= -123 + 273,15= 150,15 K

2.

T=73K

t = 73- 273,15= -200,15 C

T=290 K

t= 290-273,15= 16,85

T=400K

t= 400-273,15= 126,85