Question

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Answer 1

1,2(3)=(123-12)/90=111/90

2,3(4)=(234-23)/90=211/90

3,4(5)=(345-34)/90=311/90

4,5(6)=(456-45)/90=411/90

a=(111+211+311+411)/90=1044/90=11,6

1,(23)=(123-1)/99=122/99

2,(34)=(234-2)/99=232/99

3,(45)=(345-3)/99=342/99

4,(56)=(456-4)/99=452/99

b=(122+232+342+452)/99=1148/99=11,(59)

c=5/3+11/4+19/5+29/6 amplificam pe prima cu 20, a doua cu 15, a treia cu 12 si a patra cu 10

c=(100+165+228+290)/60=783/60=13,05

ordinea este: a, b si c