Question

f) (1+1,8^2•100):(2,4•15-0,1^3•1000•11)

Answer 1

Salutare!

$\bf (1+1,8^{2}\cdot100):(2,4\cdot15-0,1^{3}\cdot1000\cdot11)=$

$\bf \Big(1+\Big(\dfrac{18}{10}\Big)^{2}\cdot100\Big):\Big(2,4\cdot15-\Big(\dfrac{1}{10}\Big)^{3}\cdot1000\cdot11\Big)=$

$\bf \Big(1+\Big(\dfrac{9}{5}\Big)^{2}\cdot100\Big):\Big(36-\dfrac{1}{1000}\cdot1000\cdot11\Big)=$

$\bf \Big(1+\dfrac{81}{25}\cdot100\Big):\Big(36-\dfrac{1}{\not1000}\cdot\not1000\cdot11\Big)=$

$\bf \Big(1+\dfrac{81}{\not25}\cdot\not100\Big):\Big(36-11\Big)=$

$\bf (1+81\cdot 4):25=$

$\bf (1+324):25=$

$\bf 325:25=$

$\boxed{\bf 13}$