Question

f) (2^n+3×3^n+2^n×3^n+1+6^n):6^n

repede pls​

Answer 1

Răspuns:

Bănuiesc ca este vorba de aceasta scriere a exercițiului: (2^n×3^n+2^n×3^n+1+6^n):6^n

$\bf \Big(2^n\cdot 3^n+2^n\cdot3^{n+1}+6^n\Big):6^n =$

$\bf \Big[\big(2\cdot 3\big)^n+2^n\cdot3^{n}\cdot3^{1}+6^n\Big]:6^n =$

$\bf \Big[6^n+\big(2\cdot 3\big)^n\cdot3^{1}+6^n\Big]:6^n =$

$\bf \Big(6^n+6^n\cdot3^{1}+6^n\Big):6^n =$

$\bf 6^n \cdot\Big(6^{n-n}+6^{n-n}\cdot3^{1}+6^{n-n}\Big):6^n =$

$\bf 6^n \cdot\Big(6^{0}+6^{0}\cdot3^{1}+6^{0}\Big):6^n =$

$\bf 6^n \cdot\Big(1+1\cdot3^{1}+1\Big):6^n =$

$\bf 6^n \cdot\Big(1+1\cdot3+1\Big):6^n =$

$\bf 6^n \cdot\Big(1+3+1\Big):6^n =$

$\bf 6^n \cdot5:6^n =$

$\bf 6^{n-n} \cdot5=$

$\bf 6^{0} \cdot5=$

$\bf 1 \cdot5= \red{\boxed{\bf{~5~}}}$