Question

f) (4+2¹⁹²÷2¹⁸⁸)÷5
g) (1+2×2²×2⁴)÷(2⁷+1)
h) [(3³)¹²:3² ⁵-56]÷5
i) 8¹⁶÷(2÷2¹⁰)³-2¹-2⁰

va roogg repede ​

Answer 1

f)4

g)1

h)

$\frac{ {3}^{26} - 56 }{5}$

i)2¹¹

Explicație pas cu pas:

f) (4+2⁴)÷5

(4+16)÷5

20÷5

4

g)(1+2⁷)÷(2⁷+1)

(1+128)÷(128+1)

1 pentru ca imparti aceleasi expresii

h)[3³⁶:3¹⁰-56]÷5

[3²⁶-56]÷5

$\frac{ {3}^{26} - 56 }{5}$

i)8¹⁶÷4³⁰-2¹-2⁰

(2³)¹⁶÷(2²)³⁰-2¹-2⁰

2⁴⁸÷2⁶⁰-2¹-2⁰

2¹²-2¹-2⁰

2¹¹