Question

f) 402+[1002:3-(100 + a)x2]:14=408

g) 40+90:[9+48:(a+6)]=46

i) 7777-(77:7+a-7777:7+777)x7=777

j) [80x(a:16-64)x60-3980]:4=3805
Ajutaţi-mă vă rog foarte frumos!!!!

Answer 1

f) 402+[1002:3-(100+a)•2]:14=408
402+[334+(-100-a)•2]:14=408
402+(334-200-2a):14=408
402+(134-2a):14=408
402+134-2a/14=408
402+2(67-a)/14=408(simplifici 2 cu 14)
402+67-a/7=408
7•402+7•(67-a)/7=7•408
2814+67-a=2856
2881-a=2856
-a=2856-2881
-a=-25
a=25
g) 40 +90:[9+48:(a+6)]=46
40+90:(9+48/a+6)=46
40+90:(9(a+6)+48)/a+6=46
40+90:(9a+54+48)/a+6=46
40+90:(9a+102)/a+6=46 a(egal taiat)-6 a(egal taiat)-34/3
40+90•(a+6)/9a+102=46
40+90•(a+6)/3(3a+34)=46(simplifici 90 cu 3)
40+30•(a+6)/3a+34=46
40+(30(a+6))/3a+34=46
40+(30a+180)/3a+34=46
(30a+180)/3a+34=46-40
(30a+180)/3a+34=6
30a+180=6(3a+34)
30a+180=18a+204
30a-18a=204-108
12a=24
a=2,a(egal taiat,adica nu poate fi egal)-6, a(egal taiat)-34/3
i) 7777-(77:7+a-7777:7+777)•7=777
7777-(11+a-1111+777)•7=777
7777-(-323+a)•7=777
7777+(323-a)•7=777
7777+2261-7a=777
10038-7a=777
-7a=777-10038
-7a=-9261
a=1323
j) [80•(a:16-64)•60-3980]:4=3805
[80(a/16-64)•60-3980]:4=3805
[4800(a/16-64)-3980]:4=3805
(300a-307200-3980):4=3805
(300a-311180):4=3805
(300a-311180)/4=3805
4(75a-77795)/4=3805
75a-77795=3805
75a=3805-77795
75a=81600
a=1088
Sper ca te-am ajutat!