Question

f(f(x)) = 0 , f(x)=x^2-3x+2

Answer 1

Răspuns:

Explicație pas cu pas:

f(f(x))=f(x²-3x+2)=(x²-3x+2)²-3(x²-3x+2)+2

fie x²-3x+2=t

t²-3t+2=0

(t-1) (t-2) =0

t=1

x²-3x+2=1

x²-3x+1=0

x1,2=(3±√5)/2

t=2

x²-3x+2=2

x²-3x=0

x3=0

x4=3