Question

f:R->R; f(x)=2 la x - xln2

Calculati f'(x)

Ma scuzati. Sunt pe telefon si nu pot pune la putere.

Answer 1

f(x)=2^x-xln2

f'(x)=(2^x-xln2)'=(2^x)'-(xln2)'=2^x*ln2-ln2*x'=2^x*ln2-ln2=ln2(2^x-1)