Question

f:R -> R , f(x)=2x+1

Answer 1

Răspuns:

Explicație pas cu pas:

f:R -> R , f(x)=2x+1

∩ Ox <=> f(x) = 0  <=> 2x+1 = 0  => 2x = -1 => x = -1/2 => A(-1/2 ; 0)

∩ Oy <=> x = 0 => f(0) = 2·0+1 = 1  => B(0 ; 1)

f(1) = 2·1+1 = 2+1 = 3  => C(1 ; 3)