Question

F: R -> R
f(x)=2x-4
a)Aratati ca F(-2) +f(2)=-8

Answer 1

f(-2)=2(-2)-4
f(-2)=-4-4=-8

f(2)=2*2-4
f(2)=0

deci f(-2)+f(2)=-8+0=-8

Answer 2

$f(x)=2x-4 \\ f(-2)=2*(-2)-4=-4-4=-8 \\ f(2)=2*2-4=4-4=0 \\ a) f(-2)+f(2)=-8+0=-8 \\ Succese$