Question

F:R=>R
f(x)=ax+3
Determinati nr real a stiind ca f(-3)=0
#examen

Answer 1

f(  -3 ) =0
a · ( -3 ) + 3 =0 
 -3a = -3 
a = -3 : ( -3) = 1 
f(x) = x + 3

Answer 2

f(x)=ax+3

f(-3)=0
f(-3)=-3a+3

Deci, -3a+3=0
-3a=0-3
-3a=-3
3a=3
a=1