Question

f:R->R ; f(x)=x/3 + 1/2 ; determinati punctul de pe graficul f care are coordonate egale

Answer 1

x = f(x)    x = x/3 + 1/2    6x = 2x +3    4x = 3    x= 3/4       f(3/4) = 1/4 +1/2 =3/4

Answer 2

Fie G(x,x)∈$G_{f}$⇔f(x)=x⇔$\frac{x}{3} + \frac{1}{2}$=x
$\frac{2x+3}{6}=x$
2x+3=6x
4x=3
x=$\frac{3}{4}$⇒G($\frac{3}{4}; \frac{3}{4}$)