Question

f:R->R f(x)=x²+2x+m m=? Stiind ca minimul functiei este 5 a>0

Answer 1

minimul functie dee atinge pt x=-b/2a=(-2/2)=-1
f(-1)=1-2+m=m-1

m-1=5
m=6

verificare x²+2x+6=x²=2x+1+5=(x+1)²+5 al carei minim este 5
deci bine rezolvat
 as simple as that!