Question

f:R->R,
$f( \times ) = { \times }^{2} + 2 \\ f(3) + f(1) = f( - 1) + f( - 3)$
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Answer 1

Explicație pas cu pas:

f(3)=3^2+2=9+2=11

f(1)=1^2+2=3

f(-1)=(-1)^2+2=1+2=3

f(-3)=(-3)^2+2=9+2=11

f(3)+f(1)=f(-1)+f(-3)

11+3=11+3

14=14 (A)