Question

f:R-R f(x)=(a-3)x + b + 1 a si b nr reale
determinati nr a si b stiind ca pct A(-2;2) si B(3;2) apartin Gf
Pt a=3 si b=2

Answer 1

f(-2)=2

f(-2)=-2a+6+b+1.

-2a++b+7=2

-2a+b=-5. (1)

f(3)=2

f(3)=3a-9+b+1

3a+b-8=2

3a+b=10. (2)

Din (1)-(2) --> -6a=-15 --> a= 15/6

-2(15/6) +b = -5

b= -5 + 5

b=0