Question

f:R-R, f(x)=$\left \{ {{ \frac{x}{2} +2a , x\ \textgreater \ 2} \atop {ax+log_{2}x, \geq 2 }} \right.$ unde "a" este numar real.
a) Pentru a=0, calculati f(-1)·f(4).

Answer 1

pt a=0
f(x)={x/2  x<2
{log[2]x pt x≥2
f(-1)=-1/2
f(4)=log[2]4=2  
f(-1)*f(4)=-1/2*2=-1