Question

(f )va rog ajutatima;;

Answer 1

0,(6)=6/9= simplif=2/3
1 intreg 1/3=(1x3+1)/3=4/3
2 intreg 1/4=(2x4+1)/4=9/4
10/36= simplif cu 2=5/18
3intreg 1/3=(3x3+1)/3=10/3
1/1,5=1/(15/10)=10/15=simplif cu 5=2/3
ex.devine
=(2/3:4/3-9/4):(5/18-1/5x10/3)-2/3
=(2/3x3/4-9/4):(5/18-2/3)-2/3
=(1/2-9/4):[(5-2x6)/18-2/3]
=[(2-9)/4]:(-7/18)-2/3
=(-7/4)x(-18/7)-2/3
=9/2-2/3=
=(9x3-2x2)/6
=(27-4)/6=23/6=3,8(3)