Question

F) va rog. Nu inteleg cum se face

Answer 1

CH3CH2OH + O2 -bacterie acetica->CH3COOH + H2O

ms = 300 g , c = 6%

stim ca c% = mdx100/ms

=> md = msxc/100 = 300x6/100 = 18 g ac. acetic

md g...................V L.......................................... 18 g

CH3CH2OH + O2 -bacterie acetica->CH3COOH + H2O

46.........................22,4...........................................60

=> md = 46x18/60 = 13,8 g etanol

c% = 15% => ms = mdx100/ms = 13,8x100/15

=> ms = 92 g sol etanol

p = 1,02 g/cm3 (cred ca a scapat un c la unitatea de masura...!!!!)

p = ms/Vs => Vs = ms/p

=> Vs = 92 /1,02 = 90,2 cm3 sol. etanol

V(o2) = 22,4x18/60 = 6,72 L O2

Vaer = 5Vo2 = 5x6,72 = 33,6 L aer