Question

F(x)=3x-1
F(1)+f(2)+f(3)+...+f(2017)=?​

Answer 1

f(1)=3*1-1=2

f(2)=3*2-1=5

f(3)=3*3-1=8

f(2017)=3*2017-1=6050

progresie aritmetică cu r=3

r=a2-a1=5-2=3

n=(an-a1)/r+1

n=(6050-2)/3+1

n=6048/3+1

n=2016+1

n=2017

S=(a1+an)*n/2=(2+6050)*2017/2=6052/2*2017=3026*2017=6103442