Question

f(x) = 4x³ + 3x²

a) Determinati primitiva F a functiei f pentru care F(1)=2015

Answer 1

[tex]\displaystyle \int (4x^3+3x^2)dx= 4\cdot\dfrac{x^4}{4}+3\cdot \dfrac{x^3}{3}+C=x^4+x^3+C\\ \text{Deci o primitiva a f este de forma:}\\ F(x)=x^4+x^3+C\\ \text{Punem conditia ca }F(1)=2015\\ 2+C=2015\\ \boxed{C=2013}[/tex]