Question

f(x)=ln(1+1/x) calculează derivata functiei f

Answer 1

$\it \left(\ln\left(1+\dfrac{1}{x}\right)\right)' = \left(1+\dfrac{1}{x}\right)' \cdot \dfrac{1}{1+\dfrac{1}{x}} = -\dfrac{1}{x^2}\cdot\dfrac{x}{x+1}=-\dfrac{1}{x^2+x}$