Question

f’(x) ??? mulțumesc:*

Answer 1

Răspuns:

$f'(x)=(\frac{x+1}{e^{x}})'= \frac{(x+1)'*e^{x}-(x+1)*(e^{x})'}{(e^{x})^{2}}=\frac{1*e^{x}-(x+1)*e^{x}}{e^{2x}}=\frac{e^{x}*(1-x-1)}{e^{2x}}=\frac{e^{x}*(-x)}{e^{x}*e^{x}} =-\frac{x}{e^{x}}$

Explicație pas cu pas: