Question

f `(x)=(x-2)^2 + (x+2)^2 =?

Answer 1

$f(x)= (x-2)^{2} +(x+2)^2=x^2-4x+4+x^2+4x+4=2x^2+8$

$f(x)= 2(x^2+4)$

$\frac{d}{dx}f'(2x^2+8)$

$\frac{d}{dx}(2x^2)= 2\frac{d}{dx}(x^2)$

$2*2x^2^-^1=4x$

$\frac{d}{dx}(8)=0$

$\frac{d}{dx}f'(x)=4f'x$

Answer 2

Daca vrei derivata atunci e asa: 2(x-2)+2(x+2)=2x-4+2x+4=4x