Question

f(x)= -x² + 7x - 12
Aflati zerourile functiei (cu delta)

Answer 1

a=-1

b=7

c=-12

Δ=b^2-4ac = 49-(4*12) = 49-48=1 deci √Δ=1

solutiile ecuatiei:

x1=(-b+√Δ)/2a=(-7+1)/-2=-6/-2=3

x2=(-b-√Δ)/2a=(-7-1)/-2=-8/-2=4

Answer 2

Delta= b^2 -4ac = 49 -48 = 1

x.1.2 = -7+-1  /  -2 =

x1=-7-1  /  -2 = -8/-2 = 4

x2= -7 +1  / -2 = -6/-2 = 3

Verificare:

-9+21-12=0

-16+28-12=0