Question

faceti-o pe trei, va rog

Answer 1

1+6√2+18-(16√2-72+54√2-27)=
19+6√2-(70√2-99)=
19+6√2-70√2-99=
118-64√2

Answer 2

$(1 + 3 \sqrt{2}) ^{2} - (2 \sqrt{2} - 3) ^{3} \\ \\ 1 + 2 \times 3 \sqrt{2} + (3 \sqrt{2}) ^{2} - 16 \sqrt{2} + 48 - 18 \sqrt{2} + 24 - 36 \sqrt{2} + 27 \\ \\ 1 + 2 \times 3 \sqrt{2} + {3}^{2} \sqrt{2} ^{2} - 16 \sqrt{2} + 48 - 18 \sqrt{2} + 24 - 36 \sqrt{2} + 27 \\ \\ 1 + 2 \times 3 \sqrt{2} + 9 \sqrt{2} ^{2} - 16 \sqrt{2} + 48 - 18 \sqrt{2} + 24 - 36 \sqrt{2} + 27 \\ \\ 1 + 2 \times 3 \sqrt{2} + 9 \times 2 - 16 \sqrt{2} + 48 - 18 \sqrt{2} + 24 - 36 \sqrt{2} + 27 \\ \\ 1 + 6 \sqrt{2} + 9 \times 2 - 16 \sqrt{2} + 48 - 18 \sqrt{2} + 24 - 36 \sqrt{2} + 27 \\ \\ 1 + 6 \sqrt{2} + 18 - 16 \sqrt{2} + 48 - 18 \sqrt{2} + 24 - 36 \sqrt{2} + 27 \\ \\ (1 + 18 + 48 + 24 + 27) + (6 \sqrt{2} - 16 \sqrt{2} - 18 \sqrt{2} - 36 \sqrt{2}) \\ \\ 118 - 64 \sqrt{2}$