Question

faceți rapid nu doar răspunsuri rezolvari

Answer 1

$3)a) {0}^{2} = 0$

${1}^{2} = 1$

${2}^{2} = 4$

${3}^{2} = 9$

${4}^{2} = 16$

${5}^{2} = 25$

${6}^{2} = 36$

${7}^{2} = 49$

${8}^{2} = 64$

${9}^{2} = 81$

${10}^{2} = 100$

${11}^{2} = 121$

${12}^{2} = 144$

${13}^{2} = 169$

${14}^{2} = 196$

${15}^{2} = 225$

${16}^{2} = 256$

${17}^{2} = 289$

${18}^{2} = 324$

${19}^{2} = 361$

$b) {0}^{3} = 0$

${1}^{3} = 1$

${2}^{3} = 8$

${3}^{3} = 27$

${4}^{3} = 64$

${5}^{3} = 125$

${6}^{3} = 216$

${7}^{3} = 343$

${8}^{3} = 512$

${9}^{3} = 729$

$4) {2018}^{2} - 2018 - 2017$

$= 2018(2018 - 1) - 2017$

$= 2018 \times 2017 - 2017$

$= 2017(2018 - 1)$

$= 2017 \times 2017$

$= {2017}^{2} = > p.p$

$5)2 + {2}^{1} + {2}^{2} + {2}^{3} + {2}^{4} + {2}^{5}$

$= 2 + 2 + 4 + 8 + 16 + 32$

$= 4 + 4 + 8 + 16 + 32$

$= 8 + 8 + 16 + 32$

$= 16 + 16 + 32$

$= 32 + 32$

$= 64 = 8 \times 8 = {8}^{2} = > p.p$