Question

Faceti urgentttt urgentt

Answer 1

CB=AC => ∆ABC-isoscel dar m(CAB)=40°=>m(CBA)=40° dar (BD-bisectoare (CBA)=>m(CBD)=m(CBA)/2=40°/2=20°

m(AOB)=m(AB)

m(ACB)=m(AB)/2=60°=>m(AOB)=120°

∆ABC-drept in A=>Teorema Lui Pitagora AB^2+AC^2=BC^2

6^2+AC^2=10^2=>AC^2=100-36=65=>AC=8

Aria∆ABC=AB×AC/2=6×8/2=24cm^2

AM-mediana=>M-mijlocul(BC)=>BM=MC=10/2=5cm^2

Aria∆AMB=AB×BM/2=5×6/2=15cm^2

Aria∆AMC=Aria∆ABC-Aria∆AMB=24-15=9cm^2

AriaABCD=AB×AD=3×5=15cm^2